How is the function being called? What does "does not work" mean? Do you have a compilation error? If so, what is it? Does the program crash? Hang? Does the program give the wrong results? If so, what is the data, what results are you expecting, and what results do you get?

t is initialized to 0, t == 5 will always be evaluated to be false, so your for loop will never run.

update

for (t = 0; t == 5; t++) {

to

for (t = 0; t < 5; t++) {

for Statement

Executes a statement repeatedly until the condition becomes false.

for ( init-expression ; cond-expression ; loop-expression )

      statement;

Here's a way to do it that does not need too much boilerplate, inspired from http://stackoverflow.com/a/26902803/1495627 :

template<std::size_t N>
struct num { static const constexpr auto value = N; };

template <class F, std::size_t... Is>
void for_(F func, std::index_sequence<Is...>)
{
  using expander = int[];
  (void)expander{0, ((void)func(num<Is>{}), 0)...};
}

template <std::size_t N, typename F>
void for_(F func)
{
  for_(func, std::make_index_sequence<N>());
}

Then you can do :

for_<N>([&] (auto i) {      
  std::get<i.value>(t); // do stuff
});

If you have a C++17 compiler accessible, it can be simplified to

template <class F, std::size_t... Is>
void for_(F func, std::index_sequence<Is...>)
{
  (func(num<Is>{}), ...);
}

This is an infinite loop. Any of the three parts of a for loop (initialization, condition and increment) can be missing. Specifically, if the condition in a for loop is missing, it is treated as being true. So it is equivalent to while(1) { ... }.

If you are trying to typecast, you must do:

(char)x;

Not

char(x);